64 lines
2.8 KiB
C++
64 lines
2.8 KiB
C++
/******************************************************************************
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* Author: Laurent Kneip *
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* Contact: kneip.laurent@gmail.com *
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* License: Copyright (c) 2013 Laurent Kneip, ANU. All rights reserved. *
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* *
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* Redistribution and use in source and binary forms, with or without *
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* modification, are permitted provided that the following conditions *
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* are met: *
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* * Redistributions of source code must retain the above copyright *
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* notice, this list of conditions and the following disclaimer. *
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* * Redistributions in binary form must reproduce the above copyright *
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* notice, this list of conditions and the following disclaimer in the *
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* documentation and/or other materials provided with the distribution. *
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* * Neither the name of ANU nor the names of its contributors may be *
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* used to endorse or promote products derived from this software without *
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* specific prior written permission. *
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* *
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"*
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* AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE *
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE *
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* ARE DISCLAIMED. IN NO EVENT SHALL ANU OR THE CONTRIBUTORS BE LIABLE *
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL *
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR *
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* SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER *
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* CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT *
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY *
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF *
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* SUCH DAMAGE. *
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******************************************************************************/
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#include "time_measurement.hpp"
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#ifdef WIN32
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#include <sys\timeb.h>
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void
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gettimeofday( timeval * timeofday, int dummy)
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{
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struct timeb time;
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ftime(&time);
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timeofday->tv_sec = (int) time.time;
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timeofday->tv_usec = 1000 * (int) time.millitm;
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}
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#endif
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timeval
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timeval_minus( const struct timeval &t1, const struct timeval &t2 )
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{
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timeval ret;
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ret.tv_sec = t1.tv_sec - t2.tv_sec;
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if( t1.tv_usec < t2.tv_usec )
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{
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ret.tv_sec--;
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ret.tv_usec = t1.tv_usec - t2.tv_usec + 1000000;
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}
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else
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ret.tv_usec = t1.tv_usec - t2.tv_usec;
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return ret;
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}
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